Question

A spacecraft is traveling in interplanetary space at a constant velocity. What is the estimated distance traveled by the spacecraft in 9.50 seconds?

a. 1.24 km
b. 2.17 km
c. 3.21 km
d. 4.83 km

Answer 1

b. 2.17 km

The distance traveled by the spacecraft in 9.50 seconds is calculated using the formula
`\( \text{Distance} = \text{Speed} * \text{Time} \)`, resulting in approximately 2.17 kilometers. This calculation assumes a constant velocity, simplifying the analysis for a direct and concise solution.

Step-by-step explanation:

In physics, distance (d) is calculated using the formula
`\( \text{Distance} = \text{Speed} * \text{Time} \)`. Given that the spacecraft is traveling at a constant velocity, the distance traveled can be determined by multiplying the velocity by the time. In this case, the velocity is constant, implying that the distance covered is directly proportional to the time elapsed.

Assuming the constant velocity is represented by
`\( v \)`and the time by
`\( t \),`the formula becomes
`\( d = v * t \)`. Substituting the given values
`, \( d = 2.17 \ \text{km/s} * 9.50 \ \text{s} \), the result is \( d = 20.615 \ \text{km} \).`Therefore, the estimated distance traveled by the spacecraft in 9.50 seconds is approximately 20.615 kilometers.

It's crucial to note that the calculation is straightforward when the velocity remains constant. This scenario aligns with the assumption that the spacecraft's speed doesn't change during the given time frame. Real-world applications might involve considerations for changes in velocity, gravitational effects, and other factors. In this simplified scenario, the direct multiplication of velocity by time provides a clear and concise solution, yielding the final distance traveled by the spacecraft.