Question

A bar of lead has a mass of 0.556 kg. How much water would it displace, in mL, if placed into a container of water? The density of lead is 11.9 g/cm³.

a) 46.72 mL
b) 55.62 mL
c) 65.42 mL
d) 76.18 mL

Answer 1

The volume of water displaced by the 0.556 kg bar of lead is calculated by dividing the mass of the lead bar by its density, yielding 46.72 cm³ or mL. Thus, the correct answer is a) 46.72 mL.

Step-by-step explanation:

The question involves finding the volume of water displaced by a bar of lead when submerged, using the known mass of the lead and its density. Given that the mass of the lead bar is 0.556 kg (or 556 grams, since 1 kg = 1000 grams) and the density of lead is 11.9 g/cm³, we can calculate the volume of the lead and hence, the volume of water displaced (assuming that the volume of water displaced will be equal to the volume of the lead bar).

The volume ℓ is found using the formula: ℓ = mass / density. Thus, the volume of the lead bar is ℓ = 556 g / 11.9 g/cm³ = 46.72 cm³. Since 1 cm³ is equivalent to 1 mL, the volume of water displaced by the lead bar is 46.72 mL.

Therefore, the correct answer is a) 46.72 mL.

So, the correct answer is approximately 46.72 mL, which corresponds to option (a).