Question

Mrs. Humphrey is Teaching a fifth grade class. She is standing 5 m in front of Jennifer. Shane is sitting to jennifer's right. If shane and Mrs. Humphrey free are thirteen meters apart, How far apart are jennifer and shane

Answer 1

After forming a right-angled triangle using the distances given and applying the Pythagorean theorem, we find that Jennifer and Shane are 12 meters apart.

Step-by-step explanation:

To determine how far apart Jennifer and Shane are, let's visualize the positions. We'll use the information that Mrs. Humphrey is 5 meters in front of Jennifer and the distance between Shane and Mrs. Humphrey is 13 meters. Imagine a straight line from Mrs. Humphrey to Jennifer and then a right angle from Jennifer to Shane. This forms a right-angled triangle with Mrs. Humphrey and Shane at the two corners of the hypotenuse, and Jennifer at the right angle corner.

To find the distance between Jennifer and Shane, we can use the Pythagorean theorem which states, in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. If we let x be the distance between Jennifer and Shane, we can write the equation:

x2 + 52 = 132

Which simplifies to:

x2 + 25 = 169

Subtract 25 from both sides:

x2 = 144

Now, take the square root of both sides:

x = 12

So, Jennifer and Shane are 12 meters apart.