Question

Which sample contains more ions: 7.0 g of KC₂H₃O₂ or 6.0 g of Cu(NO₃)₂? Support your answer with calculations.

a) 7.0 g of KC₂H₃O₂
b) 6.0 g of Cu(NO₃)₂
c) Both have the same amount of ions
d) Need more information to determine

Answer 1

To determine which sample contains more ions, we need to calculate the number of moles of each compound and compare them. The sample of KC₂H₃O₂ contains more moles (ions) than the sample of Cu(NO₃)₂.

Step-by-step explanation:

To determine which sample contains more ions, we need to calculate the number of moles of each compound and compare them.

First, let's calculate the number of moles of KC₂H₃O₂:

Molar mass of KC₂H₃O₂ = 39.10 g/mol (potassium) + 2 * 12.01 g/mol (carbon) + 3 * 1.01 g/mol (hydrogen) + 2 * 16.00 g/mol (oxygen) = 98.14 g/mol

Moles of KC₂H₃O₂ = 7.0 g / 98.14 g/mol = 0.071 moles

Now, let's calculate the number of moles of Cu(NO₃)₂:

Molar mass of Cu(NO₃)₂ = 63.55 g/mol (copper) + 2 * (14.01 g/mol nitrogen + 3 * 16.00 g/mol oxygen) = 187.56 g/mol

Moles of Cu(NO₃)₂ = 6.0 g / 187.56 g/mol = 0.032 moles

We can see that the sample of KC₂H₃O₂ contains more moles (ions) than the sample of Cu(NO₃)₂. Therefore, the correct answer is a) 7.0 g of KC₂H₃O₂.