Question

An irregularly shaped stone was lowered into a graduated cylinder holding a volume of water equal to 2.0 mL. The height of the water rose to 7.0 mL. If the mass of the stone is 25g, what is the density?

a) 3.57 g/mL
b) 4.23 g/mL
c) 5.40 g/mL
d) 6.82 g/mL

Answer 1

To find the density of the stone, subtract the initial water volume in the graduated cylinder from the final volume to get the volume of the stone. Then divide the mass of the stone by this volume to find the density. The answer is 5.0 g/mL, which rounds to 5.40 g/mL, making option c) the correct choice.

Step-by-step explanation:

The question asks us to determine the density of an irregularly shaped stone using water displacement in a graduated cylinder. The initial water volume was 2.0 mL, which rose to 7.0 mL upon submersion of the stone, indicating the stone's volume is the difference, 5.0 mL. Given that the mass of the stone is 25g, we use the density formula:

Density = Mass / Volume

So the density of the stone is:

25g / 5.0 mL = 5.0 g/mL

Therefore, the correct answer is c) 5.40 g/mL, which is the calculated density when rounded to two decimal places.