Final answer:
When one of the zeroes of the quadratic equation x²+kx−5 is 1, substituting x with 1 and solving for k yields k=4, making option a the correct answer.
Step-by-step explanation:
If one of the zeroes of the quadratic equation x²+kx−5 is 1, we can substitute x with 1 and solve for k:
1² + k*1 - 5 = 0
1 + k - 5 = 0
k = 5 - 1
k = 4
Therefore, the value of k is 4 when one of the zeroes is 1, making option a the correct answer.