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If one of the zeroes of x²+kx−5 is 1, then k=?
a. 4
b. 5
c. 6
d. 7

1 Answer

4 votes

Final answer:

When one of the zeroes of the quadratic equation x²+kx−5 is 1, substituting x with 1 and solving for k yields k=4, making option a the correct answer.

Step-by-step explanation:

If one of the zeroes of the quadratic equation x²+kx−5 is 1, we can substitute x with 1 and solve for k:

1² + k*1 - 5 = 0

1 + k - 5 = 0

k = 5 - 1

k = 4

Therefore, the value of k is 4 when one of the zeroes is 1, making option a the correct answer.

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