Question

81.01 g CCl₄ Express your answer to four significant figures.

n=? molecules CCl₄

a) 1.21 x 10²³ molecules
b) 2.34 x 10²³ molecules
c) 3.45 x 10²³ molecules
d) 4.56 x 10²³ molecules

Answer 1

The number (n) of molecules of CCl₄ is 3.45 x 10²³ molecules (Option C). To find the number of molecules of CCl₄, we need to convert the given mass of CCl₄ to moles using the molar mass of CCl₄. Next, we can use Avogadro's number to convert the number of moles to molecules.

Step-by-step explanation:

To find the number of molecules of CCl₄, we need to convert the given mass of CCl₄ to moles using the molar mass of CCl₄.

The molar mass of CCl₄ is 153.825 g/mol.

Therefore, we have:

81.01 g CCl4 ÷ 153.825 g/mol = 0.526 mol CCl₄

Next, we can use Avogadro's number (6.022 x 10²³) to convert the number of moles to molecules:

0.526 mol CCl₄ × (6.022 x 10²³molecules/mol)

= 3.45 x 10²³ molecules CCl₄

Therefore, the correct answer is (Option C) 3.45 x 10²³ molecules.