Question

X²+x−8=0

x+5y−2=0 Find x and y.

a)x=2,y=−1

b)x=−4,y=1

c)x=−2,y=2

d)x=4,y=−2

Answer 1

To find x and y, the quadratic equation x²+x−8=0 is solved for x using the quadratic formula, yielding x=2 and x=-4. These x values are then substituted into the linear equation x+5y−2=0 to find y, resulting in the pairs (x=2, y=-1) and (x=-4, y=1)

The correct answer is option a and b

Step-by-step explanation:

The question asks us to solve for x and y given two equations: x²+x−8=0 and x+5y−2=0. To start, we can solve the first equation, which is a quadratic equation of the form ax²+bx+c=0, to find the values of x. Let's solve this using the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a).For the equation x²+x−8=0, the values of a, b, and c are 1, 1, and -8 respectively. Applying the quadratic formula, we find two possible solutions for x, which are x = 2 and x = -4.

Substituting these values of x into the second equation x+5y−2=0, we can solve for y. For x = 2, we get y = -1 and for x = -4, we get y = 1.

Therefore, the answers are: (a) x=2, y=−1 and (b) x=−4, y=1.