Question

The ingredient for an Italian dressing recipe calls for 200 mL of olive oil, 50 mL of white vinegar, and 20 mL of water. How many mL of olive oil would you need for a 1.5 L container of Italian dressing?

a) 225 mL
b) 450 mL
c) 600 mL
d) 750 mL

Answer 1

To find how much olive oil is needed for a 1.5 L container, we maintain the ratio from the original recipe. By setting up a proportion, we calculate approximately 1111.11 mL, which may suggest an error in the provided options, as the closest correct option is not listed.

Step-by-step explanation:

To calculate how much olive oil is needed for a 1.5 L container of Italian dressing, we must first determine the ratio of olive oil to the total volume of the original recipe. The original recipe contains 200 mL of olive oil, 50 mL of white vinegar, and 20 mL of water, giving a total volume of 270 mL. The ratio of olive oil to total volume is 200 mL / 270 mL. To fill a 1.5 L container (which is the same as 1500 mL), we need to maintain the same ratio.

We set up a proportion to solve for the amount of olive oil needed:

1. (200 mL olive oil) / (270 mL total) = (x mL olive oil) / (1500 mL total).
2. Multiply both sides by 1500 mL to find x.
3. x mL olive oil = (200 mL olive oil / 270 mL total) × 1500 mL total
   

After calculating, the solution yields that 1111.11 mL (approximately) of olive oil is required, which rounds to 1100 mL when considering practical use. However, since this option is not available in the multiple-choice answers, we round it to the closest option, which is 1125 mL (not provided in the options either). There may be an error in the question or the options provided. Otherwise, if rounding off to the closest higher option provided, 1200 mL would be selected, correlating to option (c) 600 mL, but considering that it would be half of the desired amount, this seems incorrect.