Question

Solve for b. Then, find the value of b when a = 6. Show all your work.

2a + 4b = 16
a) b = 2, b = 3
b) b = 3, b = 4
c) b = 4, b = 5
d) b = 5, b = 6

Answer 1

To find the value of b when a = 6 in the equation 2a + 4b = 16, first isolate b by subtracting 2a from both sides. Then, divide both sides by 4 to solve for b. Substituting a = 6 into the equation, the value of b is 1.

Step-by-step explanation:

To solve for b in the equation 2a + 4b = 16, we need to isolate b. First, subtract 2a from both sides of the equation:

2a + 4b - 2a = 16 - 2a

4b = 16 - 2a

Next, divide both sides of the equation by 4 to solve for b:

b = (16 - 2a) / 4

For the given value of a = 6, substitute it into the equation:

b = (16 - 2(6)) / 4

b = (16 - 12) / 4

b = 4/4

b = 1

Therefore, when a = 6, the value of b is 1.