Question

You add 6.3 g of iron to 22.00 mL of water and observe that the volume of iron in water together is 22.80 mL. Calculate the density of iron.

a) 6.3 g / 22.00 mL
b) 6.3 g / 22.80 mL
c) 22.80 mL / 6.3 g
d) 22.00 mL / 6.3 g

Answer 1

The density of iron is calculated by dividing the mass of the iron (6.3 g) by the volume of water it displaces (0.80 mL), which equals 7.9 g/mL.

Step-by-step explanation:

The density of iron can be calculated using the mass of the iron and the volume of water it displaces. To calculate the density, you divide the mass of iron by the change in volume of water caused by the addition of iron. Since the total volume after adding iron is 22.80 mL, and the initial volume of water was 22.00 mL, the volume of iron is 22.80 mL - 22.00 mL = 0.80 mL. The density of iron is therefore calculated as 6.3 g / 0.80 mL.

Density = mass x volume

= 6.3 g / 0.80 mL = 7.875 g/mL which, after proper significant figures, is

7.9 g/mL

.