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Find the 8th term of a geometric progression (GP) whose 1st term and common ratio are 6 and 3 respectively.

A) 14,122
B) 13,222
C) 13,322
D) 13,122
E) 14,222

1 Answer

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Final answer:

To find the 8th term of a geometric progression (GP) with a first term of 6 and a common ratio of 3, we can use the formula for the nth term of a GP: an = a1 * r^(n-1). Plugging in the values, we get a8 = 6 * 3^(8-1). Therefore, the 8th term of the given geometric progression is 13,122.

Step-by-step explanation:

To find the 8th term of a geometric progression (GP) with a first term of 6 and a common ratio of 3, we can use the formula for the nth term of a GP: an = a1 * r^(n-1). In this case, a1 = 6 and r = 3. Plugging in the values, we get a8 = 6 * 3^(8-1).

a8 = 6 * 3^7 = 6 * 2187 = 13,122.

So, the 8th term of the given geometric progression is 13,122.

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