123k views
4 votes
Find the roots of the quadratic equation 2x² - 400 + 3000.

a) x = 20, x = -75
b) x = 15, x = -100
c) x = 25, x = -120
d) x = 30, x = -150

User WileCau
by
8.9k points

1 Answer

2 votes

Final answer:

The quadratic formula was applied to find the roots of the assumed correct form of the equation 2x² - 3400. Using the formula, it was found that the solutions are x = 41.25 and x = -41.25. However, these solutions do not match the provided answer choices, indicating a possible error in the given equation.

Step-by-step explanation:

To find the roots of the quadratic equation 2x² - 400 + 3000, you need to apply the quadratic formula. The equation should be in the standard form ax² + bx + c = 0. In this case, it looks like there might be a typo in the equation, as the constant term should typically be subtracted from the other terms. If we assume the equation should be 2x² - 400 - 3000 (which simplifies to 2x² - 3400), we can then identify that a = 2, b = 0, and c = -3400. The quadratic formula is x = (-b ± √(b²-4ac)) / (2a), which simplifies to x = ± √(-4ac) / (2a) because b = 0. Substituting the values of a and c into the formula, we get x = ± √(4*2*3400) / (2*2), which simplifies to x = ± √(27200) / 4. The square root of 27200 is 165, so the solutions are x = 165/4 and x = -165/4, which are x = 41.25 and x = -41.25, respectively. There appears to be a mismatch between the provided equation and the answer choices, as none of the choices match the calculated solutions. It's important to double-check the original equation for any errors before solving.

User Elad Shahar
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.