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The measures of the sides of the triangle shown are given in inches. If this triangle forms the base of a right prism that is 10 inches long, what is the surface area of the prism?

a. 2(10x + 15) square inches
b. 2(10x - 15) square inches
c. 2(5x + 15) square inches
d. 2(5x - 15) square inches

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Final Answer:

The surface area of the prism is 2(5x - 15) square inches.

Step-by-step explanation:

To find the surface area of the prism, we need to find the area of each face and then add them up. Since the triangle at the base is a right triangle with legs of 5 inches and 12 inches, we can use the Pythagorean theorem to find the height (h) of the triangle:


h^2 = 5^2 + 12^2h^2 = 144 + 25h^2 = 169h = sqrt(169) = 13 inches\\

Now that we know the height, we can find the area of each face:

- The base is a triangle with sides of 5 inches and 12 inches, so its area is: (1/2)bh = (1/2)(5)(13) = 32.5 square inches.

- The sides are rectangles with widths of 5 inches and heights of either 10 inches (for the two longer sides) or 13 inches (for the two shorter sides). The areas of these rectangles are: (5)(10) = 50 square inches and (5)(13) = 65 square inches.

- The top is a triangle with sides of either 5 inches or 12 inches (depending on which side it's adjacent to). Its area is: (1/2)bh = (1/2)(5)(13) = 32.5 square inches or (1/2)(12)(13) = 78 square inches.

Adding up all these areas gives us the total surface area:

Surface area = base + (2 sides) + top

Surface area = 32.5 + (2)(65) + (32.5 or 78)

Surface area = 97 or 170.5 square inches

Surface area = 2(5x - 15) square inches, where x is the width of the base in inches. This formula comes from simplifying the expression for surface area using algebraic manipulation.

Question: Find the surface area of a prism with a rectangular base measuring 5 inches by 10 inches and a triangular top with a base of 12 inches and a height of 13 inches. The prism has a total of 5 identical sides, including the base and top. Use the formula for surface area of a prism to calculate the total surface area.

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