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If the ratio of AB to BC is 13:15, at what tion of AC is point B located? Round to the nearest hundredth, if necessary.

a) 0.41
b) 0.46
c) 0.52
d) 0.56

User Bobharley
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1 Answer

3 votes

Final answer:

Point B is located at 0.46 of the distance from point A to point C, based on the ratio of AB to BC which is 13:15.

Step-by-step explanation:

The question asks at what portion of AC is point B located if the ratio of AB to BC is 13:15. To find the position of point B along segment AC, we must first understand that the ratio represents the division of AC into 13 parts and 15 parts respectively, making the entire length of AC as 13 + 15 parts. Thus, the ratio of AB to the entire length of AC is 13/28 since AC is divided into 13 parts for AB and 15 parts for BC.

To find the proportional location of point B on AC, we calculate 13/28 which gives us 0.46428. Rounded to the nearest hundredth, this value is 0.46. Therefore, point B is located at approximately 0.46 of the distance from point A to point C on segment AC.

User Giuseppe Garassino
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