Question

An object is moving -10 m/s, then it accelerates for 3 seconds. Afterward, it is moving -40 m/s. Calculate the acceleration of the object using the following equation: V f = Vi + at.

(A) -10 m/s²
(B) -30 m/s²
(C) -50 m/s²
(D) -20 m/s²

Answer 1

The acceleration of the object is -10 m/s².

Step-by-step explanation:

The equation Vf = Vi + at relates to final velocity (Vf), initial velocity (Vi), acceleration (a), and time (t).

In this case, the initial velocity (Vi) is -10 m/s, the final velocity (Vf) is -40 m/s, and time (t) is 3 seconds.

Substituting the values into the equation, we get -40 m/s = -10 m/s + a * 3 s.

Simplifying the equation, we have -40 m/s = -10 m/s + 3a.

To isolate the acceleration (a), we subtract -10 m/s from both sides of the equation, resulting in -30 m/s = 3a.

Dividing both sides of the equation by 3, we find that the acceleration (a) is -10 m/s².

Therefore, the correct answer is (A) -10 m/s².