Final answer:
The correct structural formula for the product of the reaction between 1-butene and bromine is CH2BrCH=CHCH3, which represents 1-bromo-2-butene.
Step-by-step explanation:
The student's question involves a reaction between 1-butene (CH2CH=CHCH3) and bromine (Br2). This reaction is a typical halogenation in which the bromine adds across the double bond of the alkene to form a dibromoalkane. In this case, the reaction results in the 1,2-dibromo addition product, where each bromine atom attaches to a different carbon atom that was originally involved in the double bond. The correct answer from the options provided is b) CH2BrCH=CHCH3, which represents the chemical structure for 1-bromo-2-butene, the compound formed when the bromine adds to the less substituted carbon (Markovnikov's rule does not apply here since bromine is non-polar and does not form carbocations).