Question

Which of the following is a potential temperature change when 190.0 calories of heat are applied to a 125 gram sample of a metal with a heat capacity of 0.0562 cal/g oC?

a) 1.214 oC
b) 11.335 oC
c) 15.072 oC
d) 23.670 oC

Answer 1

The temperature change in the metal when 190.0 calories of heat are applied is approximately 23.670 oC.

Step-by-step explanation:

To find the temperature change in the metal when 190.0 calories of heat are applied, we can use the formula:

q = m × c × ΔT

Where:
q = heat energy
m = mass of the metal (125 g)
c = specific heat capacity of the metal (0.0562 cal/g °C)
ΔT = temperature change

Now we can rearrange the formula to solve for ΔT:

ΔT = q / (m × c)

Substituting the given values, we get:

ΔT = 190.0 cal / (125 g × 0.0562 cal/g °C)

Simplifying the equation, ΔT is approximately 23.670 °C. Therefore, the correct answer is (d) 23.670 °C.