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A tank contains 50kg of salt and 2000L of water. A solution of a concentration 0.0125kg of salt per liter enters a tank at the rate 5L/min. The solution is mixed and drains from the tank at the same rate. Let y be the number of kg of salt in the tank after t minutes. Write the differential equation for this situation part 1. dy/dt = part 2. y(0)=

User Cyx
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Final answer:

The differential equation for the concentration of salt in the tank over time is dy/dt = 0.0625 - (y/2000)*5, with an initial condition y(0) = 50 kg.

Step-by-step explanation:

The student is tasked with determining the differential equation that models the concentration of salt in a tank over time. The tank starts with 50 kg of salt and 2000L of water, and a salt solution flows in at a rate of 5L/min with a concentration of 0.0125kg of salt per liter. The mixed solution drains from the tank at the same rate it enters.

Part 1: Differential Equation for dy/dt

The rate of change of the amount of salt in the tank, denoted as dy/dt, is the difference between the rate at which salt enters and the rate at which it leaves the tank. Therefore, dy/dt is given by the equation:

dy/dt = rate in (kg/min) - rate out (kg/min)

The rate in is the concentration of the entering solution multiplied by the flow rate:

rate in = 0.0125 kg/L * 5 L/min = 0.0625 kg/min

The rate out is the concentration of salt in the tank at any time t, divided by the total volume, multiplied by the flow rate:

rate out = (y/2000 kg/L) * 5 L/min

Part 2: Initial Condition y(0)

The initial condition for the amount of salt in the tank at time t=0 minutes is:

y(0) = 50 kg

User Maximpa
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