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How many grams would 7.57 x 10^22 atoms of Zn weigh?

a) 65.38 grams
b) 127.60 grams
c) 253.80 grams
d) 16.92 grams

1 Answer

2 votes

Final answer:

To find the grams of Zn for 7.57 x 10^22 atoms, divide the number of atoms by Avogadro's number to get moles, then multiply by zinc's molar mass.

Step-by-step explanation:

To determine how many grams 7.57 x 1022 atoms of Zn (zinc) would weigh, we use Avogadro's number, which is 6.022 x 1023 atoms per mole, and zinc's atomic mass of approximately 65.4 grams per mole. First, we calculate the number of moles of Zn represented by 7.57 x 1022 atoms:

Number of moles = 7.57 x 1022 atoms / 6.022 x 1023 atoms/mol

Then we multiply the number of moles by the molar mass of Zn to find the mass in grams:

Mass of Zn = Number of moles x 65.4 g/mol

By performing these calculations, we can find the correct mass of Zn in grams that corresponds to the given number of atoms. The right answer according to the provided choices would be found once these calculations are complete.

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