Question

Cory runs is running at a speed of 6 m/s and is slowing at a rate of 1 m/s². James is running at a speed of 10 m/s and is slowing at a rate of 2 m/s². After 5 seconds, who ran farther? Enter Cory's information below d= Vi= t= a= Enter James' information below d= Vi= t= a= Who ran faster?

Answer 1

Using the kinematic equation for distance, we find that Cory ran 17.5 m, while James ran 25 m after 5 seconds. Therefore, James ran farther than Cory.

Step-by-step explanation:

To determine who ran farther after 5 seconds, we can use the equation d = Vi × t + ½ × a × t2, where d is the distance covered, Vi is initial velocity, t is time, and a is acceleration (negative for deceleration).

Enter Cory's information below:
d= Vi= 6 m/s
t= 5 s
a= -1 m/s2
Using the equation, Cory's distance is calculated as:
d = 6 m/s × 5 s + ½ × (-1 m/s2) × (5 s)2 = 30 m - 12.5 m = 17.5 m

Enter James's information below:
d= Vi= 10 m/s
t= 5 s
a= -2 m/s2
Using the equation, James's distance is calculated as:
d = 10 m/s × 5 s + ½ × (-2 m/s2) × (5 s)2 = 50 m - 25 m = 25 m

Comparing both distances, James ran farther than Cory.