Final answer:
To find the number of standard deviations above the mean for an IQ score of 132, use the formula z = (X - mean) / standard deviation. By substituting the given values, the IQ score of 132 is approximately 2.13 standard deviations above the mean.
Step-by-step explanation:
To find how many standard deviations above the mean an IQ score of 132 is, we can use the formula: z = (X - μ) / σ Where: μ is the mean IQ score (100), σ is the standard deviation (15), X is the given IQ score (132). Substituting the values into the formula, we get z = (132 - 100) / 15 = 32 / 15 = 2.13333. Therefore, an IQ score of 132 is approximately 2.13 standard deviations above the mean.