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What is the capacitance C, in microfarads, if the formula is C=0.0885kA/1,000,000 d₂ and the given values are k=6, A=12cm², and d=0.005cm?

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Final answer:

The capacitance C, calculated with the given values of k=6, A=12 cm², and d=0.005 cm, is 254.16 microfarads.

Step-by-step explanation:

To find the capacitance C in microfarads using the formula C=0.0885kA/1,000,000 d², we plug in the given values of k=6, A=12 cm² (which is 0.0012 m² in SI units), and d=0.005 cm (which is 0.00005 m in SI units). Converting the area and distance to meters is important because the units of the provided formula are based on the SI system.

Substituting the values into the formula:

C = 0.0885 × 6 × (0.0012 m²) / (1,000,000 × (0.00005 m)²) = 0.0885 × 6 × 0.0012 / (1,000,000 × 0.00005²)

C = 0.0885 × 6 × 0.0012 / (1,000,000 × 0.0000025)

C = 0.6354 / 0.0025

C = 254.16 × 10^-6 F

C = 254.16 microfarads

The capacitance C, when calculated using the provided information and converted to microfarads, is 254.16 μF.

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