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A generator supplied a load through a feeder whose impedance is Zfa = 1+j2, the load impedance Z1 = 8 + j6, and the voltage across the load is 120 V. Find the real power and reactive power supplied by the generator using per unit representation.

User Mewa
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Final answer:

To find the real power and reactive power supplied by the generator, calculate the complex power S = VI*, where V is the voltage across the load and I* is the complex conjugate of the current. The real power is Re(S) and the reactive power is Im(S).

Step-by-step explanation:

To find the real power and reactive power supplied by the generator using per-unit representation, we first need to calculate the complex power. Complex power is given by S = VI*, where V is the voltage across the load and I* is the complex conjugate of the current.

First, let's calculate the current. The load impedance Z1 and the feeder impedance Zfa can be added together to get the total impedance Zt = Z1 + Zfa. The current can be calculated as I = V / Zt.

Once we have the current, we can calculate the complex power as S = VI*. The real power is given by P = Re(S) and the reactive power is given by Q = Im(S).

User Acewin
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