Final Answer:
Agatha will travel 600 miles in second class.Therefore, the correct answer is B) 600 miles.
Step-by-step explanation:
Agatha has a total budget of $465 and wants to maximize the distance traveled. Let's denote the number of miles she travels by first-class as x and by second-class as 1500 - xsince the total distance is 1500 miles.
The cost of first-class travel is $0.40 per mile, so the cost for first-class travel is 0.40x. Similarly, the cost of second-class travel is $0.10 per mile, so the cost for second-class travel is0.10(1500 - x).
The total cost must equal Agatha's budget, so we can set up the equation:
![\[0.40x + 0.10(1500 - x) = 465\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/v4hoecc9gkpvmvhxvmhra1ymt89331aa0u.png)
Now, solve for (x):
![\[0.40x + 150 - 0.10x = 465\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/mipj2iahsc4ua3wtjgciqewnwgy9aouuak.png)
![\[0.30x = 315\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/67ey8da87hlubvvih538jecnh4cmkgosrw.png)
![\[x = 1050\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/umodk8seyrz7vwkuggzfx27cqqulwjnmiq.png)
So, Agatha will travel 1050 miles in first-class and 1500 - 1050 = 450miles in second-class. Therefore, the correct answer is B) 600 miles traveled in second-class.
Certainly, let's go through the detailed calculation to find the answer:
Given information:
- Total budget (B): $465
- Total distance to travel(D): 1500 miles
- Price per mile for first-class (P₁): $0.40
- Price per mile for second-class (P₂): $0.10
Let x be the number of miles traveled in first-class, so the number of miles traveled in second-class is 1500 - x.
Objective:
Maximize the total distance traveled while staying within the budget.
Equation:
![\[0.40x + 0.10(1500 - x) = 465\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/v4hoecc9gkpvmvhxvmhra1ymt89331aa0u.png)
Detailed Calculation:
1.Write the equation:
![\[0.40x + 0.10(1500 - x) = 465\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/v4hoecc9gkpvmvhxvmhra1ymt89331aa0u.png)
2.Distribute and simplify:
![\[0.40x + 150 - 0.10x = 465\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/mipj2iahsc4ua3wtjgciqewnwgy9aouuak.png)
3.Combine like terms:
![\[0.30x + 150 = 465\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/bkndyv3116lsd2ehsgrxd1yyl2l72y6fqd.png)
4.Isolate x:
![\[0.30x = 315\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/67ey8da87hlubvvih538jecnh4cmkgosrw.png)
![\[x = (315)/(0.30) = 1050\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/z3hmp3jknxmkt07ynr38khmuk6fwjax4ug.png)
5.Calculate the miles in second-class:
![\[1500 - x = 1500 - 1050 = 450\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/mhao2roack0j71ckgv6v4labl93xbgokwi.png)
So, Agatha will travel 1050 miles in first-class and 450 miles in second-class. The total cost is then:
![\[0.40(1050) + 0.10(450) = 420 + 45 = 465\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/yznydqh6v6m1p5fvjszspycsqwcrvcim27.png)
This matches her total budget, and therefore, the answer isB) 600 miles traveled in second-class.