Final answer:
The time taken to fall for a ball rolling with constant velocity across a cliff is approximately 0.44 seconds.
Step-by-step explanation:
To find the time taken to fall for a ball rolling with constant velocity across a cliff, we can use the equations of motion. The height of the cliff is given as 0.95 m and the horizontal distance from the edge of the cliff is given as 0.352 m. Since the ball has constant velocity, its vertical component of velocity is zero. Using the equation for vertical motion, h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity, and t is the time, we can solve for t. Plugging in the values, 0.95 = (1/2)(9.8)t^2, we get t^2 = 0.194 and t = sqrt(0.194) = 0.44 s. Therefore, the time taken to fall is approximately 0.44 seconds.