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Evaluate the number of molecules of each element in the carbohydrate described by the formula below.

(CH₂O).
Carbon:
Hydrogen:
Oxygen:
Ration of carbon, hydrogen, and oxygen:
Type of carbohydrate:

1 Answer

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Final answer:

The carbohydrate molecule with the formula (CH₂O)n has a ratio of 1:2:1 for carbon, hydrogen, and oxygen respectively. For glucose, a monosaccharide, the molecular formula is C6H12O6, indicating 6 carbon, 12 hydrogen, and 6 oxygen atoms.

Step-by-step explanation:

The carbohydrate in question can be evaluated using the stoichiometric formula (CH₂O)n, where n represents the number of carbon (C) atoms in the molecule. This formula indicates that for every carbon atom, there are two hydrogen (H) atoms and one oxygen (O) atom, giving us a carbon to hydrogen to oxygen ratio of 1:2:1. Hence, for a carbohydrate molecule like glucose, which has 6 carbon atoms (n=6), we would have the molecular formula C₆H₁₂O₆, with 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms. According to this, the type of carbohydrate glucose is a monosaccharide, which is the simplest form of carbohydrates.

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