Question

The function h(t) = -16t2 + 75t + 80 models the height in feet, h, of a ball as it is thrown into the air at time, t, in seconds. What is h(1)? Where is the ball at 1 second?

Answer 1

To find the height of the ball at 1 second using the function h(t) = -16t2 + 75t + 80, substitute 1 for t, resulting in h(1) = 139 feet. Thus, the ball is at 139 feet above the ground at 1 second.

Step-by-step explanation:

The function h(t) described by the equation h(t) = -16t2 + 75t + 80 models the height, in feet, of a ball thrown into the air over time, t, in seconds. To find the height of the ball at 1 second, we simply substitute t with 1 in the equation, resulting in h(1). Plugging in 1 for t gives us h(1) = -16(1)2 + 75(1) + 80, which simplifies to h(1) = -16 + 75 + 80, or h(1) = 139 feet. Therefore, at 1 second, the ball is at a height of 139 feet above the ground.