Final answer:
The horizontal acceleration of an 8kg bowling ball that reaches a final velocity of 9 m/s in 4 seconds is calculated using the formula a = ∆v / t, resulting in an acceleration of 2.25 m/s².
Step-by-step explanation:
To find the horizontal acceleration of an 8kg bowling ball that is pushed from a resting position to a final velocity of 9 m/s in a time of 4 seconds, you can use the formula for acceleration:
a = ∆v / t
where:
- a is the acceleration,
- ∆v is the change in velocity,
- t is the time taken.
Since the ball starts from rest, the initial velocity (∆v) is 0 m/s, and the final velocity is 9 m/s. The time taken (t) is 4 seconds. Inserting these values into our formula gives:
a = (9 m/s - 0 m/s) / 4 s = 2.25 m/s²
Therefore, the horizontal acceleration of the bowling ball is 2.25 m/s².
This calculation assumes that the only force acting on the bowling ball is the force that accelerates it horizontally, and it neglects other forces such as friction or air resistance.