Final answer:
The acceleration of the system with two boxes being pulled to the right by a force of 43.0 N can be calculated using Newton's second law of motion. The acceleration is 0.407 m/s².
Step-by-step explanation:
To calculate the acceleration of the two boxes, we can use Newton's second law of motion, which states that acceleration is equal to the net force divided by the mass of an object. In this case, the net force is the applied force pulling the boxes to the right, which is 43.0 N. The mass of the left box is 71.0 kg, and the mass of the right box is 35.0 kg. Using the formula a = F/m, we can calculate the acceleration:
a = 43.0 N / (71.0 kg + 35.0 kg)
a = 0.407 m/s²
Therefore, the acceleration of the system is 0.407 m/s².