Question

What is the end behavior of function h?

h(t)=−4.12t+11
Ast approaches negative infinity, h(t) approaches:
a. negative infinity
b. positive infinity
c. a constant

Answer 1

The end behavior of the function h(t) = -4.12t + 11 as t approaches negative infinity is that h(t) approaches negative infinity.

Step-by-step explanation:

The end behavior of the function h(t) = -4.12t + 11 as t approaches negative infinity is that h(t) approaches negative infinity.

To understand end behavior, we look at the leading term of the function, which in this case is -4.12t. The coefficient of t is negative, which means that as t approaches negative infinity, the function will approach negative infinity.

For example, let's substitute a very large negative value for t, like -100. Plugging this into the function gives us h(-100) = -4.12(-100) + 11 = 412 + 11 = 423. As t approaches negative infinity, the value of h(t) will become increasingly negative.