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What is the scalar product of vectors A⃗ = 4.30i^ + 7.20j^ and B⃗ = 5.20i^ − 2.30j^?

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Final answer:

The scalar product of vectors A ⟶ = 4.30i^ + 7.20j^ and B⟶ = 5.20i^ − 2.30j^ is calculated using the formula A ⋅ B = Ax Bx + Ay By, which results in a scalar product of 5.80.

Step-by-step explanation:

To find the scalar product (also known as the dot product) of two vectors A and B, we use the following formula:

A ⋅ B = Ax Bx + Ay By

Where Ax and Ay are the scalar components of vector A along the x and y axes respectively, and Bx and By are the scalar components of vector B along the x and y axes.

Given vectors:

A⟶ = 4.30i^ + 7.20j^

B⟶ = 5.20i^ − 2.30j^

The scalar product is calculated as:

A⋅ B = (4.30)(5.20) + (7.20)(-2.30)

A⋅ B = 22.36 − 16.56

A⋅ B = 5.80

Therefore, the scalar product of vectors A and B is 5.80.

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