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How do I solve for the following

Negative sixteen plus the quotient of a number and -4 is -3?
a. x=−5
b. x=−4
c. x=−3
d. x=−2

User Deemoe
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8.6k points

1 Answer

1 vote

Final answer:

To solve the problem, first isolate the variable term by adding 16 to both sides, then multiply both sides by -4 to solve for x, giving us x = -52. However, since x = -52 is not one of the provided options, there may be an error in the question or the options given.

Step-by-step explanation:

The problem you're trying to solve can be written as an equation: Negative sixteen plus the quotient of a number and -4 is -3. To express that mathematically, it would look like this: -16 + (x / -4) = -3. Let's solve it step by step.

First, isolate the variable term (x / -4) by adding 16 to both sides of the equation:

-16 + (x / -4) + 16 = -3 + 16
Which simplifies to:

(x / -4) = 13
Next, we solve for x by multiplying both sides by -4 (the inverse of dividing by -4):

-4 * (x / -4) = 13 * -4
And this simplifies to x = -52. However, this result is not listed in your multiple-choice options. It seems like there may have been an error in copying the problem or in the provided options. If the provided options are correct, there's no solution among them for the problem as written. Please double-check the initial question and the answer choices.

User MMK
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