Final answer:
To find the acceleration between t=10 and t=12, we would calculate the change in velocity over change in time, which is the slope of the velocity-time graph. Without the graph, we use a hypothetical example where a 4 m/s change over 2 seconds results in a 2 m/s² acceleration, not matching the given options.
Step-by-step explanation:
To determine the acceleration of the object between times t=10 and t=12, we can use the formula for acceleration which is change in velocity (Δv) over change in time (Δt). However, since the actual velocity-time graph is not provided, we'll refer to a hypothetical graph where we can find the slope within this time interval. Assuming that the velocity at t=10 and t=12 can be obtained from the graph. For instance, if the velocity changes from 20 m/s at t=10 s to 24 m/s at t=12 s, the acceleration would be calculated as:
- Δv = final velocity - initial velocity = 24 m/s - 20 m/s = 4 m/s
- Δt = final time - initial time = 12 s - 10 s = 2 s
- Acceleration (a) = Δv / Δt = 4 m/s / 2 s = 2 m/s²
So, if the velocity increases by 4 m/s over the course of 2 seconds, the acceleration would be 2 m/s². The options provided do not include this answer, suggesting that the student may need to look at the actual graph to accurately determine the acceleration or consider that the hypothetical scenario might be incorrect.