Question

Evaluate f(2) when f(d) = 2d - 5. Evaluate f(-3.2) when f(t) = -16t + 7.8t + 12. Evaluate f(2) when f(x) = 4.

Answer 1

To evaluate the functions for specific inputs, substitute the input value into the function's equation and simplify: f(2)=-1 for the first function, f(-3.2)=38.24 for the second function, and f(2)=4 for the constant function.

Step-by-step explanation:

To solve these problems, we will evaluate the function for the given inputs, which is a standard procedure in algebraic manipulation.

• For the function f(d) = 2d - 5, we need to find f(2). So we substitute d with 2: f(2) = 2(2) - 5 = 4 - 5 = -1.
• For the function f(t) = -16t + 7.8t + 12, we evaluate f(-3.2). Substituting t with -3.2 gives: f(-3.2) = -16(-3.2) + 7.8(-3.2) + 12 = 51.2 - 24.96 + 12 = 38.24.
• For the function f(x) = 4, which is a constant function, f(2) is simply the constant value: f(2) = 4.