50.4k views
2 votes
Andrew bought some candy. He divided it into 3 bags and then ate 2 pieces of candy from one bag. He now has 113 pieces of candy in that bag. How many pieces of candy did Andrew have at the start? Write and solve an equation to support your answer.

a. 119
b. 123
c. 127
d. 131

1 Answer

2 votes

Final answer:

The original number of candy pieces in one bag was 115 before Andrew ate 2 pieces, leaving him with 113 pieces in that bag.

Step-by-step explanation:

Andrew had originally a certain number of candy pieces before he ate 2 pieces from one bag. After eating 2 pieces, he has 113 pieces left in that bag. To find the original number of candy pieces in that bag, we need to add the 2 pieces that he ate back to the current amount. So the equation to represent this situation is:

x - 2 = 113

where x is the original number of pieces in the bag before Andrew ate the 2 pieces. Now, we solve for x:

x = 113 + 2

x = 115

Since he divided the candy equally into 3 bags, we multiply the number of candies in one bag by 3 to find the total amount of candy that Andrew had at the start:

Total candy at the start = 3 × 115

Total candy at the start = 345 pieces

This result is not present among the multiple choice options provided because they concern the individual bag's original count. The correct option for the number of candy pieces in one bag before Andrew ate the 2 pieces is therefore 115.

User SimonSparks
by
8.3k points