Final answer:
The linear velocity of a point on the edge of a circular path with a radius of 10 inches and making 3 revolutions in 2 seconds is approximately 94.24 inches per second.
Step-by-step explanation:
The linear velocity of a point on the edge of a circular path can be found using the formula:
v = r * ω
where v is the linear velocity, r is the radius of the circular path, and ω is the angular velocity.
In this case, the radius of the circular path is given as 10 inches and the object makes 3 revolutions in 2 seconds. To calculate the angular velocity, we can use the formula:
ω = 2π * n / t
where n is the number of revolutions and t is the time in seconds. Plugging in the values, we get:
ω = 2π * 3 / 2 = 3π rad/s
Substituting the values of r and ω into the formula for linear velocity, we get:
v = 10 * 3π = 30π inches/s ≈ 94.24 inches/s
Therefore, the linear velocity of a point on the edge of the wheel is approximately 94.24 inches/s.