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A jet accelerates at 8.5m/s² for 10 seconds after traversing a 160m runway. How far has it traveled after 10 seconds from being at rest?

A. 425 meters
B. 550 meters
C. 680 meters
D. 850 meters

1 Answer

1 vote

Final answer:

To calculate the total distance traveled by the jet after it has been accelerating for 10 seconds from rest, we use the formula for uniformly accelerated motion, taking into account the initial distance covered. Upon reviewing the calculations, we find a discrepancy in the provided multiple choice options.

Step-by-step explanation:

The question is asking for the total distance a jet travels after it has been accelerating for 10 seconds from rest. We know from physics that when an object accelerates from rest, the distance traveled can be found using the formula for uniformly accelerated motion:

s = ut + \(\frac{1}{2}\)at^2

where:

  • s is the distance,
  • u is the initial velocity (which is 0 in this case since the jet starts from rest),
  • a is the acceleration,
  • and t is the time.Since the initial velocity u is 0 and the acceleration a is 8.5 m/s², and the time t is 10 seconds, we can substitute these values into the formula:

s = 0 \(\times\) 10 + \(\frac{1}{2}\) \(\times\) 8.5 m/s² \(\times\) 10 s^2

s = \(\frac{1}{2}\) \(\times\) 8.5 m/s² \(\times\) 100 s^2 = 425 meters

Additionally, we need to add the distance covered before the jet started to accelerate, which is given as 160 meters, to the distance covered during acceleration.

Total distance = 425 m + 160 m = 585 meters

However, since 585 meters is not an option in the multiple-choice answers, we should revisit the calculations to ensure accuracy. Notifications of any typos or miscalculations should be reported as they affect the result of the student's query.

User Rohit Jangid
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