Question

The width of a rectangle is 12 units. Can the perimeter (x) of the rectangle be 60 units when its length (y) is 18 units?

a) No, the rectangle cannot have x=60 and y=18 because x+y is less than 60.
b) No, the rectangle cannot have x=60 and y=18 because x+y is less than 24.
c) Yes, the rectangle can have x=60 and y=18 because x=12+28.
d) Yes, the rectangle can have x=60 and y=18 because x=24+24.

Answer 1

Yes, a rectangle with a width of 12 units can have a perimeter of 60 units when its length is 18 units because the perimeter formula P = 2l + 2w gives us P = 2(18) + 2(12), which equals 60 units.

Step-by-step explanation:

To determine if a rectangle with a width of 12 units can have a perimeter of 60 units when its length is 18 units, we need to use the formula for perimeter of a rectangle, which is:

P = 2l + 2w

Where P is the perimeter, l is the length, and w is the width.

Using the given width (w) of 12 units and length (l) of 18 units, we can calculate the perimeter:

P = 2(18) + 2(12)

P = 36 + 24

P = 60 units

Therefore, the answer is d) Yes, the rectangle can have x=60 and y=18 because the perimeter is the sum of twice the length plus twice the width, which amounts to 60 units in this case.