Final answer:
Using the density of ethanol (0.789 g/mL), we can calculate the volume of 103 g of ethanol to be 130.5 mL. For the second part, converting 1.1 inches to cm and using the volume of a cylinder formula reveals that 130.5 mL of ethanol would reach a height of about 4.5 cm in a graduated cylinder. The answer is A: 130.5 mL, 4.5 cm.
Step-by-step explanation:
To solve part a, we need to convert the mass of ethanol to volume using the given density. Knowing the mass of ethanol (103 g) and its density (0.789 g/mL), we can calculate the volume of liquid ethanol required by using the formula Volume = Mass / Density. Dividing 103 g by 0.789 g/mL gives us approximately 130.5 mL of ethanol.
For part b, we need to calculate the height the ethanol would reach in a graduated cylinder. The formula for the volume of a cylinder is V = πr²h, where V is the volume, r is the radius, and h is the height. Converting 1.1 inches to centimeters gives us a diameter of approximately 2.794 cm, hence a radius of 1.397 cm. By rearranging the cylinder volume formula to solve for h, we can find the height of ethanol in the cylinder (130.5 mL or 130.5 cm³). Substituting the values, we find that h is approximately 4.5 cm. The correct answer is A: 130.5 mL, 4.5 cm.