Final answer:
The rate of change of the skydiver's position concerning time is -10 m/sec. This is the average velocity at which the skydiver falls, and it is negative because the direction of the fall is towards the Earth. The graph of the magnitude of the acceleration versus time would decrease to near zero as the skydiver reaches terminal velocity.
Step-by-step explanation:
Since the skydiver falls 100 meters in 10 seconds and starts at 0 meters, the rate of change can be calculated using the formula: Rate of change = Δdistance / Δtime, Δdistance = Final position - Initial position = 100 meters - 0 meters = 100 meters, Δtime = Final time - Initial time = 10 seconds - 0 seconds = 10 seconds. Thus, the rate of change is 100 meters / 10 seconds = 10 m/sec. Since the skydiver is falling downwards, the direction of motion is towards the Earth, and by convention, this is usually taken as a negative direction in physics. Therefore, the rate of change should be indicated as negative, which gives us -10 m/sec as the correct answer. If this concept were to be graphed with acceleration on the y-axis and time on the x-axis, the magnitude of the acceleration versus time for a falling skydiver would decrease as they near terminal velocity due to air resistance. The shape of the graph would start high and taper off to nearly a flat line as the acceleration decreases to near zero.