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What is the rate for the second order reaction A - Products when [A] = 0.371 M? (k = 0.761 M-'s-1)

A. 0.169 M/s
B. 0.284 M/s
C. 0.497 M/s
D. 0.623 M/s

1 Answer

1 vote

Final answer:

Using the formula for the rate of a second order reaction, the calculated rate is 0.1047 M/s, which does not match any of the provided options, suggesting an error in the question details or choices.

Step-by-step explanation:

The rate of a second order reaction can be calculated using the formula rate = k[A]^2, where k is the rate constant and [A] is the concentration of reactant A. Given that k = 0.761 M-1s-1 and the concentration of A, [A], is 0.371 M, we can substitute these values into the equation:

rate = 0.761 x (0.371)^2 = 0.761 x 0.137641 = 0.1047 M/s

This rate is not one of the options provided in the question indicating a potential error in the given answer choices or in the question details itself. Nevertheless, using the provided rate constant and concentration, 0.1047 M/s is the correct rate calculation based on the information given.

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