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How many nickel atoms are in the coin with a mass of 10.0 g and 20% nickel by mass?

a. 2.05 x 10^22
b. 4.30 x 10^22
c. 1.03 x 10^23
d. 1.03 x 10^24

User Mickeal
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1 Answer

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Final answer:

To find the number of nickel atoms in a coin, first find the mass of nickel in the coin, convert that to moles using nickel's atomic mass, and then multiply the moles by Avogadro's number. The answer is 2.05 x 10²² nickel atoms.

Step-by-step explanation:

To calculate the number of nickel atoms in a coin with a mass of 10.0 g and 20% nickel by mass, you can use the following steps:

  1. Determine the mass of nickel in the coin by calculating 20% of 10.0 g, which equals 2.0 g.
  2. Convert grams of nickel to moles using the atomic mass of nickel (58.7 g/mol). This is done by dividing the mass of nickel by the atomic mass:


2.0 g ÷ 58.7 g/mol = 0.0341 mol

  1. Calculate the number of atoms by multiplying the number of moles by Avogadro's number (6.022 × 10²³ atoms/mol):


0.0341 mol × 6.022 × 10²³ atoms/mol = 2.05 × 10²² atoms

Therefore, the number of nickel atoms in the coin is 2.05 × 10²², which corresponds to answer choice a. 2.05 x 10²².

User Gifty
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