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A hockey team played a total of 136 games last season. The number of games they won was 20 more than three times the number of games they lost. If x represents the number of games lost, write an equation to find x and determine the number of games the team lost.

a) 3x+20=136, x=38 games lost
b) 3x−20=136, x=38 games lost
c) 3x+20=136, x=32 games lost
d) 3x−20=136, x=32 games lost

1 Answer

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Final answer:

Based on the conditions given, the hockey team lost 29 games, which is determined by setting up an equation with the total number of games played and solving for the number of games lost.

Step-by-step explanation:

The question pertains to creating an equation based on the given conditions of a hockey team's wins and losses. If x represents the number of games the team lost, then the total number of games played was 136. The number of games won is said to be 20 more than three times the number of games lost. Therefore, we can write the equation as:

Number of wins = 3x + 20

Since the total number of games (won and lost) is 136, the equation accounting for all the games is:

Total games = Number of games won + Number of games lost

136 = (3x + 20) + x

136 = 4x + 20

Subtract 20 from both sides:

116 = 4x

Divide both sides by 4 to solve for x:

x = 29

So, the number of games the team lost is 29. Therefore, the correct option would be:

c) 3x + 20 = 136, x = 29 games lost

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