Final answer:
The percentage of kittens weighing less than 4.8 lbs is 97.5%, which is not one of the options provided. The Empirical Rule was used to calculate this value, and the normal distribution defines how data points are spread out from the mean.
Step-by-step explanation:
Using the Empirical Rule, which applies to normally distributed data, we can answer the question about the weight of adorable, fluffy kittens. The Empirical Rule states that approximately 68% of data falls within one standard deviation of the mean, 95% within two standard deviations, and 99.7% within three standard deviations.
First, we need to determine how many standard deviations away from the mean 4.8 lbs is. With a mean (μ) of 3.6 lbs and a standard deviation (σ) of 0.6 lbs, we find that 4.8 lbs is two standard deviations above the mean (4.8 - 3.6 = 1.2 lbs, and 1.2 lbs / 0.6 lbs per standard deviation = 2 standard deviations). According to the Empirical Rule, 95% of the data falls within two standard deviations of the mean, and because the normal distribution is symmetric, half of this percentage (95%/2 = 47.5%) corresponds to the amount above the mean.
Therefore, to find the percentage of kittens that weigh less than 4.8 lbs, we add 50% (representing the percentage less than the mean) to 47.5%, resulting in: 97.5%. This means that the percentage of adorable, fluffy kittens that weigh less than 4.8 lbs is 97.5%, which was not one of the provided options (A) 84%, (B) 89%, (C) 94%, (D) 96%).