Question

Isotonic Saline solutions, needed for many medical applications, contain 0.9% (mass/volume) salt. If a typical IV bag can hold 1.00 L of solution, what mass of salt is required to prepare 1.00 L of isotonic saline solution?

A) 9 g
B) 8.1 g
C) 10 g
D) 9.9 g

Answer 1

To prepare 1.00 L of an isotonic saline solution containing 0.9% salt, the mass of salt required is 9 g.

Step-by-step explanation:

To prepare 1.00 L of an isotonic saline solution containing 0.9% salt, we need to calculate the mass of salt required. The concentration of the solution is given as 0.9% (mass/volume). We can use the formula for mass/volume percent: % m/v = (mass of solute / volume of solution) x 100%. So, in this case, the mass of salt required is (0.9 g / 100 mL) x 1000 mL = 9 g. Therefore, the correct answer is option A) 9 g.