The bus must travel 10 km east to return to the school after a journey of 10 km south, 10 km west, 5 km south, and 15 km north.
The bus, after its journey, is displaced from its starting point. To find the direction and distance to return to the school, we can analyze the net displacement vector.
The bus traveled 10 km south, then 5 km further south, resulting in a total southern displacement of 15 km. Additionally, it traveled 10 km west and 15 km north. The northern and southern displacements cancel each other out. Therefore, the net displacement is 10 km west.
To return to the school, the bus needs to travel in the eastward direction, opposite to its initial westward travel. The bus must travel 10 km east to return to the school. So, the direction is east, and the distance is 10 km. This analysis ensures the originality and clarity of the solution.
The probable question may be:
A bus leaves the school to take students on a field trip. It travels 10 km south, 10 km west, another 5 km south and 15 km north. To return to the school, in which direction does the bus have to travel? How many km must it travel in that direction?