Final answer:
The magnitude of acceleration of the electron is 2.63 × 10^13 m/s².
Step-by-step explanation:
To find the magnitude of acceleration of an electron in a magnetic field, we can use the equation:
a = |eV|B/m
where a is the magnitude of acceleration, e is the charge of the electron, V is the velocity of the electron, B is the magnetic field strength, and m is the mass of the electron.
Given e/m = 1.76 × 10^11 C/kg, V = 2.5 x 10^6 m/s, and B = 2.0 G (which is equal to 2.0 x 10^-4 T), we can substitute these values into the equation to calculate the magnitude of acceleration:
a = |(1.76 × 10^11 C/kg)(2.5 x 10^6 m/s)(2.0 x 10^-4 T)|
Simplifying the expression, we get:
a = (1.76 × 2.5 x 2.0) x (10^11 x 10^6 x 10^-4)
a = 2.63 x 10^13 m/s²
Therefore, the magnitude of acceleration of the electron is 2.63 × 10^13 m/s².