Final answer:
The Olympic-sized swimming pool will hold 2500 tons of water when filled to the brim, as the volume of the pool is 2500 cubic meters and the density of water is 1 ton per cubic meter.
Step-by-step explanation:
To calculate the number of tons of water an Olympic-sized swimming pool can hold, we first need to find the volume of water the pool contains and then convert it into mass using the given density of water. The dimensions of the pool are 50.0 m long, 25.0 m wide, and 2.0 m deep. The volume V of a rectangular prism (which is the shape of the swimming pool) is given by V = length × width × depth. Thus, the volume of the pool is V = 50.0 m × 25.0 m × 2.0 m = 2500 m³.
Once we have the volume, we use the density of water to find the mass. The density of water is 1.00 g/mL, which is also equivalent to 1 ton/m³ since 1 ton is equal to 1,000,000 grams (1,000 kg), and there are 1,000 liters (1,000,000 mL) in a cubic meter. Therefore, each cubic meter of water weighs 1 ton.
To find the total weight of the water in tons, we simply multiply the volume of the pool by the density of water: mass = volume × density = 2500 m³ × 1 ton/m³ = 2500 tons. Thus, the pool filled to the brim will hold 2500 tons of water, which corresponds to option A.