Question

Write an equation in slope intercept form (y = mx + b) that passes through point ( -4, - 5) and is parallel to y= -2x - 5 this is a question i need help with

A. y = -2x - 3
B. y = -2x - 5
C. y = -2x - 7
D. y = -2x + 3

Answer 1

To find the equation of a line parallel to y = -2x - 5, we need to use the same slope of -2. By plugging in the given point and slope into the slope-intercept form, we find that the equation is y = -2x - 13.

Step-by-step explanation:

To find the equation of a line parallel to a given line, we need to use the same slope as the given line. The given line has a slope of -2. Since the desired line is parallel, it must also have a slope of -2. We can use the point (-4, -5) to find the equation in slope-intercept form (y = mx + b). Using the slope (-2) and the point (-4, -5), we can substitute these values into the equation y = mx + b: -5 = -2(-4) + b, -5 = 8 + b, b = -13. Therefore, the equation in slope-intercept form is y = -2x - 13. Hence, the correct answer is D. y = -2x + 3.